In the last class I asserted that it was possible to approximate certain not-nice functions like and by -nice functions. For example, I asserted that for all and there exists a function which is -nice and approximates the -step-function in the following sense: for ; for ; and, for .
There was a question in class as to whether this could really be possible. Specifically, if is for all , and it's smooth, then it has all derivatives equal to for all . Shouldn't this make it everywhere?
Well, not so. It's true that for any , all derivatives are . But Taylor's theorem does not force such a function to be everywhere. Remember that Taylor (for smooth functions) just says that for any , for some .
For a concrete example, consider the function which is for , and is for . It's easy to see that is smooth on and it's not hard to check that its derivatives, of all orders, at (when approached from inside) are .
In fact, functions like (known as bump functions or mollifiers) are what one uses to create functions like -- essentially, by taking , where denotes the actual discontinuous step function, denotes convolution, and denotes a compressed version of , viz., .
Wednesday, April 04, 2007
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